asked 170k views
5 votes
A cyclist is traveling at 7m s¹, then accelerates at 2.5m s2 for 15 seconds.

a.
How far did they travel during this time
What was the final speed after 15 seconds?
b.

asked
User Veda
by
8.5k points

1 Answer

3 votes

Answer:

a)


{ \tt{s = ut + (1)/(2) {at}^(2) }} \\ \\ { \tt{s = (7 * 15) + (1)/(2) * 2.5 * {15}^(2) }} \\ \\ { \tt{s = 105 + 281.25}} \\ { \tt{s = 386.25 \: m}}

b)


{ \tt{v {}^(2) = {u}^(2) + 2as}} \\{ \tt{ {v}^(2) = {7}^(2) + (2 * 2.5 * 386.25)}} \\ { \tt{ {v}^(2) = 1980.25}} \\ { \tt{v = 44.5 \: m}}

answered
User Plugie
by
8.0k points
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