Question

(a³b¹²c²) × (a³c²) × (b³c¹) ⁰ =

12.4
O A. a¹5¹24
○ в. a³b¹¹c³
8
O c. a³b¹²4
OD. a¹4b¹5c9

Answer 1

Answer C is correct

Explanation:

We know that,

`\sf \: {x}^(a) * {x}^(b) = {x}^(a + b) \\ \\ \sf \frac{ {x}^(a) }{ {x}^(b) } = {x}^(a - b) \: \: \: \: \: \: \: \:`

`\sf (x) ^(0) = 1 \rightarrow \: Any \: number \: to \: the \: power \: 0 \: is \: 1`

Let us solve it now.

`\sf( {a}^(3) {b}^(12) {c}^(2) ) * ( {a}^(5) {c}^(2) ) * ( {b}^(5) {c}^(4) )^(0) \\ \sf( {a}^(3) {b}^(12) {c}^(2) ) * ( {a}^(5) {c}^(2) ) * 1 \: \: \: \: \: \: \: \: \: \: \: \\ \sf {a}^(3) * {a}^(5) * {b}^(12) * {c}^(2) * {c}^(2) * 1\\ \sf {a}^(3 + 5) * {b}^(12) * {c}^(2 + 2) * 1 \: \: \: \: \: \: \: \: \: \: \: \\ \sf {a}^(8) * {b}^(12) * {c}^(4) * 1 \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \sf {a}^(8) {b}^(12) {c}^(4) \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:`