asked 76.3k views
3 votes
Solve the equation

3x/3x-1 + 2/x = 1

asked
User Akela
by
9.2k points

2 Answers

5 votes

Answer:

x= 2/7

Explanation:

Multiply both sides by the common denominator

3x^2 +6x−2=3x^2 −x

Move everything to the left side.

3x^2+6x-2-3x^2+x=0

Simply.

7x-2=0

Separate the cosntants and variables.

7x=0+2

Add or subtract zero

7x=2

Then divide both sides by 7.

7x/7=2/7

Cancel out common factors in the numerator and denominator

x=2/7

answered
User Luca Ritossa
by
7.1k points
3 votes

Answer:

x = 2/7

Explanation:

You want to solve the equation 3x/(3x-1) + 2/x = 1.

Solution

It works nicely to subtract 1 from both sides, then simplify.


(3x)/(3x-1)+(2)/(x)=1\\\\(3x)/(3x-1)\cdot(x)/(x)+(2)/(x)\cdot(3x-1)/(3x-1)-(x(3x-1))/(x(3x-1))=0\\\\(3x^2+6x-2-3x^2+x)/(x(3x-1))=0\qquad\text{combine terms}\\\\(7x-2)/(x(3x-1))=0\qquad\text{simplify}\\\\7x-2=0\qquad\text{expression is 0 when numerator is 0}\\\\\boxed{x=(2)/(7)}\qquad\text{add 2, divide by 7}

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Additional comment

The values x=0 and x=1/3 would make the denominator zero, so are excluded from the domain of the equation. By working the problem this way, we ensure that extraneous solutions do not present themselves.

answered
User Steven Rosato
by
7.9k points

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