Question

PLEASE ANSWER WITH A VALID ANSWER. Write the equation of the line in slope intercept form passing through the points (3, -6) and perpendicular to the line Y=2/3x + 1

Answer 1

y = −3x/2 − 3/2

Explanation:

The equation of the line in the slope-intercept form is y=2x/3 + 1

The perpendicular slope ( m1) is negative reciprocal of the slope m

m1 = -1/m = -1 divide by 2/3 = -3/2

The slope of the perpendicular line is negative inverse: m = −3/2

So, the equation of the perpendicular line is y=−3x/2 + a

To find a, we use the fact that the line should pass through the given point: −6 = (−3/2) ⋅ (3) + a

Thus, a = −3/2

Therefore, the equation of the line is y = −3x/2 − 3/2

heres a picture of the graph