Question

Need Help ASAP

Write the equation of the line that passes through (5, −2) and is perpendicular to y = 5/3 x-3.

Answer 1

First option

Explanation:

Slope of the given equation = 5/3

Slope of perpendicular line will be -ve of reciprocal of the given slope

Therefore slope of perpendicular line = -3/5

let's apply point slope formula

`(y - y _(1)) = m(x - x _(1))`

point is (5,-2) and slope m = -3/5

`y - ( - 2) = ( - 3)/(5) (x - 5) \\ y + 2 = ( - 3)/(5) (x - 5) \\ y + 2 = ( - 3)/(5) x + 3 \\ y = ( - 3)/(5)x + 1`