A boy throws a ball straight up into the air. It reaches the highest point of its flight after 4 seconds-How fast was the ball going when it left the boy's hand?

Question

asked Nov 20, 2023 134k views

1 Answer

LIvanov · Answer 1 · 2023-11-24T14:03:17+0000

Answer:

Answer is

$4g \: m {s}^( - 1)$

Step-by-step explanation:

We have to find the initial velocity, u.

Final velocity is v = 0. And acceleration is due to gravity.

Now,

v = u + at

$0 = u + ( - g)m {s}^( - 2) * 4s$

$u = 4g \: m {s}^( - 1)$

Therefore, the final answer depends on the value of g.