Question

What is the length of the long leg in the right triangle shown below? O A. 6 B. 3 C. 643 D. 6√2 30* N 60°​

Answer 1

c.) 6√3

Explanation:

This can be solved using both sine and cosine rule.

1st method:

`\sf sin(x) = (opposite)/(hypotenuse)`

`\sf sin(60) = (long \ leg)/(12)`

`\sf long \ leg= 12sin(60)`

`\sf long \ leg= 6√(3)`

2nd method:

`\sf cos(x) = (adjacent)/(hypotenuse)`

`\sf cos(30) = (long \ leg)/(12)`

`\sf long \ leg= 12cos(30)`

`\sf long \ leg=6√(3)`