Question

what do i do when my algebra has something like this 9x+45=15x+3/7x im used to having constants and variables on both sides​

Answer 1

x = 2 11/12

Explanation:

First of all, on the right you have to combine 15x+3/7x which equals 15 3/7x.

9x + 45 = 15 3/7x

-9x -9x Next step is to subtract 9x from both sides.

45 = 15 3/7x

/ /

15 3/7 15 3/7 Third step is to divide 15 3/7 on both sides to leave x

by itself.

35/12 = 2 11/12 = x

x = 2 11/12