Question

What is the equation of the line that is perpendicular to the line y=3/5x+10 and passes through the point (15,-5)?

y=3/5x-20
y=-3/5x+20
y=5/3x-20
y=-5/3x+20

Answer 1

Answer: Option (4)

Explanation:

Perpendicular lines have slopes that are negative reciprocals of each other, so the slope of the line we want to find is -5/3.

Of the options, the only one that satisfies this is choice 4.