asked 7.9k views
4 votes
How do i solve y=3(0)^3-2(0)^2+13

1 Answer

1 vote

Answer:

y = 13

Explanation:

You want to "solve" y=3(0)^3-2(0)^2+13.

Evaluation

An exponent signifies repeated multiplication. That is ...

(0)^3 = 0×0×0

Of course, anything times zero is zero, so the first and second terms are both zero:

3(0)³ -2(0)² = 0 -0 = 0

Adding 0 to 13 does not change its value.

y = 3(0³) -2(0²) +13 = 0 -0 +13

y = 13

__

This is one that can be evaluated "by inspection." In general, a polynomial evaluated at x=0 will have the value of the constant term: all of the variable terms become zero.

If that is too much work, you can always enter the expression into your calculator.

answered
User Hader
by
8.5k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.