Question

Can anyone help me find the answer to the attatched question

Answer 1

Angle BOC = 120°

Angle DOC = 60°

Angle ODC = 90°

Explanation:

Triangle ABC is an equilateral triangle, therefore Angle BAC = 60°.

Now that we know Angle BAC, we can find Angle BOC: 2 × 60 = 120°

Angle DOC = ½ Angle BOC ( Radius drawn from centre to midpoint of chord, bisect the angle)

So Angle DOC = ½ (120) = 60°

Angle = 90° because D is the midpoint of chord BD and OD is a radius.