What is d if (3d-2)/(8) = -d+16(1)/(4)

Question

What is d if
`(3d-2)/(8) = -d+16(1)/(4)`

Answer 1

Answer: d=12

Explanation:

`\displaystyle\\(3d-2)/(8) =-d+16(1)/(4) \\\\(3d-2)/(8) =-d+(16*4+1)/(4) \\\\(3d-2)/(8) =-d+(64+1)/(4) \\\\(3d-2)/(8) =-d+(65)/(4)`

Multiply both parts of the equation by 8:

`\displaystyle\\3d-2=(-d+(65)/(4) )(8)\\\\3d-2=-8d+65*2\\\\3d-2=-8d+130\\\\3d-2+2=-8d+130+2\\\\3d=-8d+132\\\\3d+8d=-8d+132+8d\\\\11d=132\\`

Divide both parts of the equation by 11:

`d=12`