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0 votes
Find f '(a).
f(x) =
(1)/(√(x) +5)

asked
User Aaraeus
by
8.4k points

1 Answer

7 votes

Answer:


f'(a)=(1)/(2a^(3/2)+20a+50√(a))

Explanation:


f'(x)=((d)/(dx) (√(x)+5)(1)-(√(x)+5)(d)/(dx)(1))/((√(x)+5)^2) \\ \\ =((1)/(2√(x)))/((√(x)+5)^2) \\ \\ =((1)/(2√(x)))/(x+10√(x)+25) \\ \\ =(1)/(2x^(3/2)+20x+50√(x)) \\ \\ \therefore f'(a)=(1)/(2a^(3/2)+20a+50√(a))

Find f '(a). f(x) = (1)/(√(x) +5)-example-1
answered
User Jyao
by
7.6k points

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