Question

Help asap please!! I don’t understand

Answer 1

Answer: 2+
`(6x-2)/(x(x-3))` ==> x
`\\eq`0, x
`\\eq`3

Explanation:

f(x)=2x^2-2

g(x)=x^2-3x

(f/g)(x)=

`(2x^2-2)/(x^2-3x)`=

`(2x^2-6x+6x-2)/(x^2-3x)`=

`(2x^2-6x+6x-2)/(x^2-3x)`=

2+
`(6x-2)/(x^2-3x)`=2+
`(6x-2)/(x(x-3))` ==> x
`\\eq`0, x
`\\eq`3