Question

Solve the inequality and express your answer in interval notation.
X^2+8x+5<0

Answer 1

Answer: (-4-\sqrt{11}11 , -4+\sqrt{11}11 )

x^2+8x+5<0

x^2+8x+16-11<0

(x+4)^2-11<0

(x+4)^2<11

x+4<\sqrt{11}11

x<-4+\sqrt{11}11

x+4>-\sqrt{11}11

x>-4-\sqrt{11}11

(-4-\sqrt{11}11 , -4+\sqrt{11}11 )

Answer 2

Answer: (-4-
`√(11)`, -4+
`√(11)`) ==> B

Explanation:

x^2+8x+5<0

x^2+8x+16-11<0

(x+4)^2-11<0

(x+4)^2<11

x+4<
`√(11)`

x<-4+
`√(11)`

x+4>-
`√(11)`

x>-4-
`√(11)`

(-4-
`√(11)`, -4+
`√(11)`) ==> B

Remember, the solution doesn't include the x values -4-
`√(11)` and -4+
`√(11)` since if they were plugged in x^2+8x+5, the expression would equal 0. The expression is supposed to be LESS than 0, not equal to 0.