Question

Please help me and don’t look on the internet

Answer 1

Question 1

`\left((-5+2)/(2), (5-5)/(2) \right)=\boxed{\left(-(3)/(2), 0 \right)}`

Question 2

Let the coordinates of the other endpoint be (x,y).

`\left((x + 4)/(2), (y+8)/(2) \right)=( - 6,4) \\ \\ \implies (x + 4)/(2)=6 \implies x= - 16\\ \\ (y+8)/(2)=4 \implies y=0`

So, the coordinates of the other endpoint are (-16,0).