What is the magnitude and direction (right or left) of the net force acting on the box? N to the

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asked Aug 26, 2023 3.7k views

2 Answers

SatheeshJM · Answer 1 · 2023-09-01T05:44:16+0000

The net force is the sum of all forces, acting on an object. The net force acting on the object is 12N to the right.

From the figure (see attachment), we have:

$\bf F_N = 12NFN=12N$ :- upward force

$\bf F_g = 12NFg=12N$ :- downward force

$\bf F_p = 15NFp=15N$ :- rightward force

$\bf F_f = 3NFf=3N$ :-leftward force

The net vertical force is 0, because the upward and downward force are the same.

The magnitude of the net force is then calculated as follows:

$\bf F_(Net) = +F_p$

$\bf F_fFNet=+Fp−Ff$

$\bf F_(Net) = +15N$

$\bf 3NFNet=+15N−3N$

$\bf F_(Net) = 12NFNet=12N$

Because the force at the right is greater than the force at the left, the direction of the object is right.

Hence, the net force acting on the object is 12N to the right.