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A train traveling at 27.5 m/s accelerates to 42.2 m/s over 75.0 s. what is the displacement of the train in this time period?

1 Answer

1 vote

Answer:

Formular

S=((u+v)/2)t

S= ((27.5+42.2)/2)75

S= 2,613.75 m #

Hope this help!!!

answered
User Alexey Biryukov
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