Question

How many moles of solute particles are present in 1 mL of aqueous 0.060 M (NH4)2CO3?

Answer 1

Molarity = moles of solute/volume of solution (litres)

n = Molarity x Volume

n = 0.033 mol/L x 10^-3 L

n = 3.3 x 10^-5 moles