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Cannot solve this....
asked
Sep 18, 2023
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Cannot solve this....
Mathematics
college
SaadK
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Answer:
Multiplying gives
, which still has an irrational number for a denominator
Ivan Stoyanov
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Sep 23, 2023
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Ivan Stoyanov
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![\frac{7\sqrt[3]{x}}{\sqrt[3]{x^2}}](https://img.qammunity.org/2023/formulas/mathematics/college/qab7n3oi20wypd66ip4djzevyjc7czipiz.png)
, which still has an irrational number for a denominator