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Find the pythagorean theorem for the corresponding n=5

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User Apalomer
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Answer:

here's your answer

FOR A NUMBER "n" WE CAN FIND A PYTHAGOREAN TRIPLET AS 2n,n^2-1 and n^2+1

If the no. is n = 5, the Pythagorean triplet will be, 2n =2×5=10

n^2-1 = 5×5-1=24

n^2+1 = 5×5+1=26

So, the required Pythagorean triplet are,

10,24,26.

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User Sibylle
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