Question

How much water should be added to 10 ml of 3.00 m hcl(aq) in order to dilute it to a 2.00 m solution of hcl(aq)?

Answer 1

M1V1 = M2V2

Plug in the given values and solve for V2:

(3.00 M)(10 mL) = (2.00 M)(V2)

V2 = 15 mL

The question asks how much water should be added to the original solution, so subtract by the original amount, V1:

15 - 10 = 5 mL