Question

If a+b=2,find the value of a³+b³+6ab​

Answer 1

8

Explanation:

a³+b³+6ab

=(a+b)(a^2-a*b+b^2)+6ab

=2(a^2-a*b+b^2)+6ab

=2a^2-2a*b+2b^2+6a*b

=2a^2-2ab+6ab+2b^2

=2a^2+4ab+2b^2

=2(a^2+2ab+b^2)

Here,

(a^2+2ab+b^2) is the formula of (a+b)^2

Soo,

=2(a+b)^2

=2(2)^2

=2*4

=8