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(2sin(x) - 1 ) (tan(x) - 1) = 0 for 0 ≤ x ≤ 2π

(2sin(x) - 1 ) (tan(x) - 1) = 0 for 0 ≤ x ≤ 2π
asked 132k views
4 votes
(2sin(x) - 1 ) (tan(x) - 1) = 0
for 0 ≤ x ≤ 2π

asked
User Luie
by
7.6k points

1 Answer

3 votes

Answer:

Explanation:

hello : here is an solution

(2sin(x) - 1 ) (tan(x) - 1) = 0 for 0 ≤ x ≤ 2π-example-1
answered
User Onkar Musale
by
8.2k points
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