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A softball needs to hit a bucket 43. 0 m away on flat ground. if it is aimed at 72. 0, what must its inital velocity be?

asked
User Ecathell
by
8.3k points

1 Answer

1 vote

Answer:

This can easily be solved using the "range" formula

R = V0^2 * sin 2θ / g

V0^2 = g R / sin 2θ = 9.80 * 43 / sin 144 = 717 m^2/s^2

V0 = 26.8 m/s

answered
User Chriga
by
8.3k points
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