Question

10POINTS !!

the sum of the length of a side of two squares is 18cm and the sum of their areas is 212 cm^2. find the length of a side of the smaller square​

Answer 1

square one sides = 14, 14

square 2 sides = 4, 4

14 + 4 = 18

14 x 14 + 4 x 4 = 212

Explanation:

14 x 14 + 4 x 4

this is the area of the 2 being added

the sides lengths are 14 and 4

Answer 2

Explanation:

length

a + b = 18cm

a = 18 - b

Area

a² + b² = 212cm²

(18-b)² + b² = 212

324 - 36b + b² + b² = 212

2b² - 36b + 112 = 0

b² - 18b + 56 = 0

b² - 4b - 14b + 56 = 0

b(b-4) -14(b - 4) = 0

(b-4) (b-14) = 0

b-4 = 0 OR. b-14 = 0

b = 4 cm b = 14 cm

so 4cm < 14cm

so , length of a side of the smaller square is 4cm .......

And , large square's = 14cm .....