Question

LOTS OF POUNT PLS HELP

Answer 1

Option 2

Explanation:

Using the quadrstic formula,

`\tan \theta=\frac{-2 \pm \sqrt{2^2 - 4(√(3))(-√(3))}}{2√(3)} \\ \\ =(-2 \pm 4)/(2√(3)) \\ \\ =(-1 \pm 2)/(√(3)) \\ \\ = -√(3), (1)/(√(3))`

Case 1

`\tan \theta=-√(3) \implies \theta=(2\pi)/(3), (5\pi)/(3)`

Case 2

`\tan \theta=(1)/(√(3)) \implies \theta=(\pi)/(6), (7\pi)/(6)`