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5 votes

\int_(1)^(7) (1)/(x^(8)) d x
\int_{1}^{7} \frac{1}{x^{8}} d x​

1 Answer

5 votes

Use the power rule,


\displaystyle \int x^n \, dx = (x^(n+1))/(n+1) + C

with
n=-8. It follows by the fundamental theorem of calculus that


\displaystyle \int_1^7 (dx)/(x^8) = -\frac1{7x^7} \bigg|_(x=1)^(x=7) = -\frac17 \left(\frac1{7^7} - \frac1{1^7}\right) = \boxed{\frac17 - \frac1{7^8}}

answered
User Killscreen
by
8.5k points
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