Question

PLLLLLEASE T_T PLLLEASE

Answer 1

`{\qquad\qquad\huge\underline{{\sf Answer}}}`

let's solve ~

`\qquad \sf  \dashrightarrow \: \cfrac{4}{y - 6} + \cfrac{5}{y + 3} = \cfrac{7y - 4}{ {y}^(2) - 3y - 18}`

`\qquad \sf  \dashrightarrow \: \cfrac{4(y + 3) + 5(y - 6)}{(y - 6)(y + 3)} = \cfrac{7y - 4}{ {y}^(2) - 3y - 18}`

`\qquad \sf  \dashrightarrow \: \cfrac{4y + 12 + 5y - 30}{ {y}^(2) + 3y - 6y - 18 } = \cfrac{7y - 4}{ {y}^(2) - 3y - 18}`

`\qquad \sf  \dashrightarrow \: \cfrac{9y - 18}{ {y}^(2) - 3y - 18 } = \cfrac{7y - 4}{ {y}^(2) - 3y - 18}`

`\qquad \sf  \dashrightarrow \: 9y - 18 = 7y - 4`

[ denominator is same, so numerator must have same value to be equal ]

`\qquad \sf  \dashrightarrow \: 9y - 7y = - 4 + 18`

`\qquad \sf  \dashrightarrow \: 2y = 14`

`\qquad \sf  \dashrightarrow \: y = 7`