Question

Geometry question confused on how to solve this answer

Answer 1

The acute angles of a right triangle are complementary, so
`\boxed{m\angle F=34^(\circ)}`.

Using right-angle trigonometry, we know that

`\cos 56^(\circ)=(26)/(DF)\\\\DF=(26)/(\cos 56^(\circ))\\\\\boxed{DF \approx 46.5}`

`\tan 56^(\circ)=(FE)/(26)\\\\FE=26 \tan 56^(\circ)\\\\\boxed{FE \approx 38.5}`