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3 votes
2sin^2(x)+sin(2x)=2

please help!!

asked
User Cyroxis
by
8.8k points

1 Answer

3 votes


2sin {}^(2) (x) + sin(2x) = 2 \\ 2sin {}^(2) (x) + 2sin(x)cos(x) = 2 \\ sin {}^(2) (x) + sin(x)cos(x) - 1 = 0 \\1 - cos {}^(2) (x) + sin(x)cos(x) - 1 = 0 \\ - cos {}^(2) (x) + sin(x)cos(x) = 0


cos(x)( - cos(x) + sin(x)) = 0


cos(x) = 0 \\ x = (\pi)/(2) + k\pi \\ \\ sin(x) = cos(x) \\ x = (\pi)/(4) + k\pi

answered
User Konse
by
8.9k points

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