Question

A triangle has vertices at coordinates $(11,1)$, $(2,3)$ and $(3,7)$. What is the number of units in the length of the longest side of the triangle

Answer 1

10 units

Explanation:

the longest length is from (11, 1) to (3, 7) and can be clearly shown when graphed

now to find the length you must use the pythagorean theorem

the distance between 11 and 3 is 8 and the distance between 1 and 7 is 6 so

8^2 + 6^2 = c^2

64 + 36 = c^2

100 = c^2

c = 10

that is your answer