Question

The procedure calls for 2.0 ml of concentrated nitric acid. how many moles is this?

Answer 1

ρHNO₃= 1.51 g/cm3

ρ = m/V

m = ρ x V

m = (1.51 g/cm3)(2 cm3)= 3.02 g de HNO₃

n = m/PM = 3.02 g/63.01 g/mol = 0.0479 mol de HNO₃

Step-by-step explanation:

2 mL of concentrated nitric acid equals 0.0479 mol