Question

Find the integrals:
∫1÷(x(㏑x-π)^4)dx

Answer 1

`C-(1)/(3(lnx- \pi)^3).`

Explanation:

`\int\ {(1)/(x(lnx- \pi)^4) } \, dx=\int\ {(d(lnx- \pi))/((lnx- \pi)^4)} \, dx=-(1)/(3(lnx- \pi)^3) +C.`