Question

Which equation represents a circle that contains the point (-2, 8) and has a center at (4, 0)?

Distance formula: √(x₂-x₁)² + (V2 - V₁)²
O(x-4)² + y² = 100
O(x-4)2 + y² = 10
O x² + (y-4)² = 10
O x² + (y-4)² = 100

Answer 1

(x-4)² + y² = 100

Explanation:

The only circles that have a center at (4 , 0) are :

(x-4)² + y² = 100

(x-4)² + y² = 10

……………………

• (-2 - 4)² + 8² = (-6)² + 64 = 36 + 64 = 100 ≠ 10

Then

The circle (x-4)² + y² = 10 doesn’t contain the point (-2, 8)

• (-2 - 4)² + 8² = 100

Then

The circle (x-4)² + y² = 100 contains the point (-2, 8)