Question

Find the solutions of each equation on the interval [0,2pi)

sin(3pi/2+ x)+sin(3pi/2 +x)= -2

Answer 1

x=0

Explanation:

You can combine the equation to get 2sin(3/2 +x) = -2

divide both sides by 2 and you get the equation equal to -1. sin is equal to -1 when the value inside is 3/2 so this is the answer.