Question

4. Calculate the empirical formula for the following compounds Na=32.4% S=22.6 % O=45.0%

Answer 1

Na2 S O4

Step-by-step explanation:

Na mole wt 22.989

32.4 / 22.989 = 1.4093

S mole wt = 32.06

22.6/32.06 = .7049

O mole wt = 15.999

45 / 15.999 = 2.8127 Now divide all of the results by the smallest

Na 1.4093 / .7049 = 2

S .7049/.7049 = 1

O 2.8127 /.7049 = 4 so Na2 S O4