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H(t)=t^4+3t^2-t+3 h'?

H(t)=t^4+3t^2-t+3 h'?
asked 73.1k views
5 votes
H(t)=t^4+3t^2-t+3
h'?

asked
User Nicksweet
by
7.9k points

1 Answer

3 votes

Answer:
h'(t)=4t^3 + 6t-1

Explanation:

Use the power rule for differentiation.

answered
User PuerNoctis
by
7.2k points
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