A baseball "diamond" is actually a square with sides of 90 feet. If a runner tries to steal second base, how far must the catcher, at home plate, throw to get the runner "out"? (Distance across the diagonal)

A baseball "diamond" is actually a square with sides of 90 feet. If a runner tries to steal second base, how far must the catcher, at home plate, throw to get the runner "out"? (Distance across the diagonal)

180 feet

13.4 feet

90 feet

127.3 feet

2 Answers

A baseball "diamond" is actually a square with sides of 90 feet. If a runner tries to steal second base, how far must the catcher, at home plate, throw to get the runn…

Please log in or register to add a comment.

Please log in or register to answer this question.

2 Answers

Please log in or register to add a comment.

Please log in or register to add a comment.

Related questions

Categories

Other Questions