Register

A box has a volume given by the trinomial x^3 + 4x^2 — 32x. What are the possible dimensions of the box?

A box has a volume given by the trinomial x^3 + 4x^2 — 32x. What are the possible dimensions of the box?
asked 196k views
16 votes
A box has a volume given by the trinomial x^3 + 4x^2 — 32x. What are the possible dimensions of the box?

asked
User Ahmet Altun
by
7.8k points

1 Answer

6 votes

Answer:

x(x-4)(x+8)

Explanation:

Factor.

x(x^2+4x-32)

x(x-4)(x+8)

answered
User Dianne
by
7.7k points
← Prev Question Next Question →

No related questions found

Ask a Question
Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.

Categories

Other Questions

How do you can you solve this problem 37 + y = 87; y =
What is .725 as a fraction
How do you estimate of 4 5/8 X 1/3
Link Copied!