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In ΔHIJ, the measure of ∠J=90°, the measure of ∠I=15°, and IJ = 9.5 feet. Find the length of HI to the nearest tenth of a foot.

In ΔHIJ, the measure of ∠J=90°, the measure of ∠I=15°, and IJ = 9.5 feet. Find the length of HI to the nearest tenth of a foot.
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In ΔHIJ, the measure of ∠J=90°, the measure of ∠I=15°, and IJ = 9.5 feet. Find the length of HI to the nearest tenth of a foot.

asked
User Kenmistry
by
7.4k points

1 Answer

4 votes

Answer:9.8

Explanation:

answered
User Andreas Siegel
by
7.7k points
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