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In ΔBCD, the measure of ∠D=90°, the measure of ∠B=53°, and CD = 5.5 feet. Find the length of BC to the nearest tenth of a foot.

In ΔBCD, the measure of ∠D=90°, the measure of ∠B=53°, and CD = 5.5 feet. Find the length of BC to the nearest tenth of a foot.
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In ΔBCD, the measure of ∠D=90°, the measure of ∠B=53°, and CD = 5.5 feet. Find the length of BC to the nearest tenth of a foot.

asked
User Karoline
by
8.1k points

1 Answer

8 votes

Answer:

6.9

Explanation:

answered
User Artem Khaustov
by
8.5k points
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