Question

Z2 + (2j – 3)z + (5 – j) = 0

Answer 1

2z+(2j-3)z+(5-j)=0

2z +2jz-3z+5-j=0

2z-3z+2jz-j=-5

-z+2jz-j=-5

2jz-z-j=-5

I hope this help