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C6H12O6 -> 2C2H5OH + 2CO2Determine the volume of carbon dioxide gas produced when 7.0 moles of glucose decomposes at STP

C6H12O6 -> 2C2H5OH + 2CO2Determine the volume of carbon dioxide gas produced when 7.0 moles of glucose decomposes at STP
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C6H12O6 -> 2C2H5OH + 2CO2Determine the volume of carbon dioxide gas produced when 7.0 moles of glucose decomposes at STP

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User Samsina
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2 Answers

8 votes
The answer is 313.6!
answered
User Parreirat
by
7.6k points
2 votes

Answer:

313.6 L

Step-by-step explanation:

use mole/mole ratio to find moles of CO2 (=14)

multiply by 22.4

=313.6 L

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User Pabce
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