Find the Degree, Leading Term, and Leading Coefficient of this equation. 6j^3+\frac{\sqrt{1(2)/(10) } }{5}

Question

Find the Degree, Leading Term, and Leading Coefficient of this equation.


`6j^3+\frac{\sqrt{1(2)/(10) } }{5}`

Answer 1

the coeficent is 190

Explanation:

I think this right but wait for more people to answer I haven't done this type of math in 3 years trust me it gets better