Question

NO LINKS!! Please help with these notes. Part 5a.​

Answer 1

#1

Here

• b=10
• m=7
• c=10

`\\ \tt\hookrightarrow log_57=(log_(10)7)/(log_(10)10)`

`\\ \tt\hookrightarrow (log_(10)7)/(1)`

`\\ \tt\hookrightarrow log_(10)7`

#2

• b=e
• m=8
• c=e

`\\ \tt\hookrightarrow log_38=(log_e8)/(log_ee)`

`\\ \tt\hookrightarrow (log_e8)/(1)`

`\\ \tt\hookrightarrow log_e8`