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If 8x is the length of a rectangle and the area is 8x^2 -56x what must the width be?​

If 8x is the length of a rectangle and the area is 8x^2 -56x what must the width be?​
asked 126k views
11 votes
If 8x is the length of a rectangle and the area is 8x^2 -56x what must the width be?​

asked
User JBeckton
by
8.6k points

1 Answer

6 votes

Answer:

width= x-7

Explanation:

l= 8x

Area = l*b

b= 8x^2-56x/8x

b= 8x(x-7)/8x

b= x-7

answered
User AndreasRu
by
8.3k points
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