Question

What is the 100th term of the sequence with a1 = 222 and d = -5?

1.-273
2.-278
3.717
4.722

Answer 1

Answer: the 100th term of the sequence =-273 (1)

Explanation:

Since the first term = 222

and d (common difference )=-5 Then we are talking about an arithmetic progression

The nth term of an Arithmetic progression is given as

Tn=a + (n - 1)d

Therefore given that n =100

Tn=a + (n - 1)d = 222 +(100-1)-5

222+ (99)-5

222-495=-273