Question

A ball is thrown up at a 60 degree angle and lands in 18.5 seconds. what is the initial velocity of the ball?

Answer 1

Given :-

`\sf \bullet \: \theta = {60}^( \circ)`

`\sf \bullet \:Time \: of \: flight , \: t = 18.5 \: s`

To Find :-

`\bullet \sf \: Initial \: velocity , \: u`

Solution :-

`\bf \star\boxed{ \bf t = (2u \: sin \theta)/(g) }`

`: \implies \sf 18.5 = (2u \: sin60)/(10)`

`: \implies \sf \: 2u \: sin60 = 185`

`: \implies \sf u = (185 * 2)/( √(3) * 2 )`

`: \implies \sf u = (185)/(1.73)`

`\bf: \implies u = 107 \: m {s}^( - 1)`