Question

Rocket is launched from a tower. The height of the rocket, y in feet, is related to the

time after launch, a in seconds, by the given equation. Using this equation, find out
the time at which the rocket will reach its max, to the nearest 100th of a second.
y=16x^2+ +225x+79

Answer 1

7.03 seconds

Explanation:

First, you need to differentiate the equation (The derivative of y represents the rocket's velocity):

y' = 32x + 225

Then, set y' to 0 and solve for x

0 = 32x + 225

x = 7.03s